6.4 Circuits Involving Two Energy Storage Elements cont.

Example 6-6 cont.

KCL for the (dynamic) t ³ 0 situation below yields: [10V. - v(t)] / 4 W - i(t) - 0.05dv(t)/dt + [5V. - v(t)] / 4 W = 0 A. which has solution:

i(t) = 3.75 - (12.5t + 2.5)e-5t A., t ³ 0

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