6.4 Circuits Involving Two Energy Storage Elements cont.

Example 6-6 cont.

v(t) = (A1 + A2t)e-5t and

dv(t)/dt = A2e-5t - 5e-5t(A1 + A2t)

So v(0+) = A1 = 0 V. and

dv(0+)/dt = A2 - 5A1 = 50 V./Sec.

\ A1 = 0 V. and A2 = 50 V./Sec. so that

v(t) = 0 V., t £ 0 v(t) = 50te-5t V., t ³ 0

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