6.2 The RC Circuit cont.
To see how to use the generic solution in this case, reconsider the RC circuit and let R= 2 W and C = 3 F so that the circuit’s KCL becomes: 3dv(t)/dt + v(t)/2 = iS(t)
Which in generic form is: dv(t)/dt + v(t)/6 = iS(t)/3
By inspection, the time constant is T = RC = 6 Sec.
and the generic solution is: v(t) = [v(0) - vSS(0)]e-t/6 + vSS(t)