PPT Slide

5.6 Average Power, Reactive Power and Power Factor¾Maximum Power Transfer cont.

Example 5-4 cont.

As a result of the transformer’s turns ratio, I = (N1/N2) I’

\ I = (N1/N2) I’ = 2´3Ö2/ -45° A. = (6Ö2)/ -45° A. so that

i(t) = (6Ö2)cos(t - 45°) A. » 8.485cos(t - 45°) A.

and IRMS = |I|/Ö2 = 6 A. so that Pave., max. = (IRMS)2 ´ 5 W yields:

Pave., max. = 180 W.

j30 W

-j10 W