5.6 Average Power, Reactive Power and Power Factor Correction: An Application
Example 5-3 cont. With correction, the source produces SSource = SNet + SLine = (12 KW + j9 KVAR ) + (1.56 KW + j0 KVAR) = 13.56 KW + j9 KVAR = 16.27/33.57° KVA \ the apparent power is 16.27 KVA, the power factor is cos(33.57°) Lag = 0.83 Lag and IRMS = 125 A. so that VSource = 16.27 KVA / 125 A. = 130 V. (RMS)