5.6 Average Power, Reactive Power and Power Factor Correction: An Application
Example 5-3 cont. Without correction, the source produces SSource = SLoad + SLine = (12 KW + j16 KVAR) + (2.78 KW + j0 KVAR) = 14.78 KW +j16 KVAR = 21.78/42.27° KVA \ the apparent power is 21.78 KVA and the power factor is cos(42.27°) Lag = 0.74 Lag