5.6 Average Power, Reactive Power and Power Factor Correction: An Application cont.
The load’s complex power is SLoad = P + jQ = 12 KW + jú SLoad çsin(q) = 12 KW + j20 KVA x 0.8 = 12 KW + j16 KVAR
Next, add -j7 KVAR of capacitance in parallel with the load to obtain ...