5.6 Average Power, Reactive Power and Power Factor¾Example 5-2 cont.
Phasor circuit: w = 3 Rad./Sec., jwL = j3x2 = j6 W, -j(1/wC) = -j5 W , and the source phasor is 2/0° A.
By current ¸, I = [-j5 W/(5 W + j6 W -j5 W)]2/0° A. Ergo, I » 1.961/-101.3° A. and by KCL, IC = 2/0° A. - I Ergo IC » 3.063/38.89° A. and V = -j5 W x IC » 15.32/-51.1° V.