5.4 Use of Complex Exponential Source cont.
Therefore, i(t) = Iej3t » 1.49/-63.43°ej3t A. » 1.49e-j63.43°ej3t A. » 1.49ej(3t-63.43°) A.
If Vs(t) = 10cos(3t) V. = Re[10ej3t V.], what’s i(t)?
i(t) » Re[1.49ej(3t-63.43°) ] » 1.49cos(3t - 63.43°) A.
If Vs(t) = 10sin(3t) V. = Im[10ej3t V.], what’s i(t)?
i(t) » Im[1.49ej(3t-63.43°) ] » 1.49sin(3t - 63.43°) A.
The final task is to develop a method to streamline the calculations even further