PPT Slide

Example 3-10 cont.

First find VTh = open-circuit voltage across terminals 1 & 3

KCL at Node 1: [(-17V.) - VTh]/3W + 2A. - I = 0 A. (A.)

KCL at Node 2: I - 2A. - V2/2W - 2A. = 0 A. (B.)

KVL: VTh + 6V. - V2 = 0 V. (C.)

(A.), (B.) and (C.) have solution VTh = -12.8 V.