3.5 Node Voltage Analysis: Example 3-5
There are three nodes (m, n and the Ref. node)
Vm is known to be 5 V. (by inspection or by KVL)
Write KCLs at nodes where the voltage is unknown
KCL at node n: (0V.- Vn)/2W + (5V.- Vn) /2W + 3A. = 0 A. ¾which has solution Vn = 5.5 V.