PPT Slide
Section 12.9: The Nonideal Transformer and its Equivalent Circuits cont.
Calculate the previous example’s all-day efficiency if it’s load schedule is as follows: Full-load at 0.8 lagging power factor for 12 hours, no-load for 4 hours and half-load at unity power factor for 8 hours
The output load energies are:
Full load: 150 KVA´0.8´12 hours = 1440 KWH.
Half load: (150 KVA´1.0/2)´8 hours = 600 KWH.
Total daily load energy = Wout = 2040 KWH