PPT Slide

In the air gap:

Hg = Bg/m0 = 1 T./(4p´10-7 H/m.) = 7.95´105 A/m.

Fg = mmfg = Hglg = (7.95´105 A/m.)´(0.1´10-3m.) = 79.5 AT

In the core:

fc = fg \ BgAg = BcAc, ergo Bc = Bg´(Ag/Ac). But Ac = SF´Ag,

\ Bc = Bg/SF = 1 T./0.9 = 1.11 T.

Then for the M-19 core material (Fig. 12.6), Hc = 130 A/m. \

Fc = mmfc = Hclc = (130 A/m.)´(0.1 m.) = 13 AT

Section 12.4: Examples 12.1 and 12.2

Coil: 50 Turns

Core: 15-mm-thick laminations of M-19 Steel,

length = 10 cm, area = (2.5 cm)2

Air gap: 0.1 mm long, flux density = 1 T.

Calculate the coil’s current in Amperes

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