PPT Slide

P3ph = 6 MW = Ö3 ´ 11 KV ´ |Il| ´ 0.8 (= Ö3|Vll| |Il|cosq)

\ |Il| » 393.6 A. Then

Q3ph = Ö3|Vll| |Il|sinq = Ö3 ´ 11 KV ´ 393.6 A. ´ 0.6 » + 4.5 MVAR (Note that Q3ph > 0 since the power factor is lagging)

Section 11.4 Wye-Delta Equivalence cont.

Example 11.6 (p. 467) cont.

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